If the area of the auxiliary circle of the ellipse $\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1\left( {a > b} \right)$ is twice the area of the ellipse, then the eccentricity of the ellipse is

  • A

    $\frac{1}{{\sqrt 2 }}$

  • B

    $\frac{{\sqrt 3 }}{2}$

  • C

    $\frac{1}{{\sqrt 3 }}$

  • D

    $\frac{1}{2}$

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